Question

10 over 2- square root of 5 given this radical expression, rationalize the denominator .

Answer 1

sorry, it's -(20+10sqrt5)

Answer 2

wouldnt it be 20+10 sqrt 5/ -3 or -20-10 sqrt 5

Answer 3

yes, if you distribute the negative sign that is what you would get

Answer 4

so -20-10 sqrt 5

Answer 5

to rationalize stuff like this, just multiply both the numberator and the denominator by the conjugate of what term with the sqrt in it. Yes, that is right.

Answer 6

For this one 3 sqrt of -4 lies between two consecutive integers what are the integers.... I don't know how to start this? Would you happen to know.

Answer 7

I know it has to do with imaginary numbers, but I haven't done that since beginning of high school. I'm sure if you post it as a question someone else will be able to help you out.

Answer 8

Yeah, I haven't done this in so LONG. But I will post it, thanks for your help!

Answer 9

Anytime! Good luck

Answer 10

\[10\over2-\sqrt{5}\]Is this the problem?

Answer 11

Yes.

Answer 12

O.K multiply top and bottom by\[2+\sqrt{5}\]this will give you
\[10(2+\sqrt{5})\over -1\] or \[-20-10\sqrt{5}\]Actually there is no imaginary component to this it is a irrational number.

Answer 13

the imaginary comment was about a different problem.

Answer 14

Oh we figured this one out, we were trying to figure out another equation that is as follows 3 square root of -4 lies between two consecutive integers what are the two consecutive integers.

Answer 15

Oh very well, good luck with this, and complex numbers with imaginary component are quite useful in the field of electronics.

Answer 16

\[\sqrt[3]{-4}\] the A is a 3...That is what the equation looks like.

Answer 17

sqrt(-4) is 2i

Answer 18

I know the square root of 4 is 2. That is not my question... My question is what two consecutive integers lie between the equation 3 square root of -4....

Answer 19

\[\sqrt[3]{-4}\] Is also not imaginary

Answer 20

The solution is a negative value real and irrational.

Answer 21

-1.587401052