Use implicit differentiation to find the slope of the tangent line to the curve {y/{x - 7 y} = x^{9} + 3 at the point ( 1, (4/29) ).
\[\frac{y}{x-7y}=x^9+3\]?
yes that is the curve
take the derivative implicitly. you need the quotient rule on the left. you should get \[\frac{(x-7y)y'-y(1-7y')}{(x-7y)^2}=9x^8\]
id kill the fraction and product rule it for a cleaner feel and a fresher scent
do some algebra, plug in the numbers and solve for y'
better idea!
from grease to shine in half the time...
\[\frac{y}{x-7y}=x^9+3\] \[y=(x^9+3)(x-7y)\] \[y'=(x^9+3)'(x-7y)+(x^9+3)(x-7y)'\] \[y'=(9x^8)(x-7y)+(x^9+3)(x'-7y')\]
i definitely liked your second method better lol thank you!
Thank you for explaining the first method too, figuring how to do it that way was killing me until you explained it
the quotient rule is inherently a nightmare ...
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