Question

derivative of (3x)(4x) derivative of (3x)(4x) @Mathematics

Answer 1

24x

Answer 2

=f'g + fg'= 12x+12x= 24x

Answer 3

take the log
\[\ln(3x\times 4x)=\ln(3x)+\ln(4x)=\ln(3) + \ln(x)+\ln(4)+\ln(x)\] take the derivative get
\[\frac{1}{x}+\frac{1}{x}=\frac{2}{x}\] then multiply by the original function get
\[(3x)(4x)\times \frac{2}{x}\] you can simplify if you want

Answer 4

woah, thats too complicated for me

Answer 5

satelitte thats wrong, you have to use the product rule

Answer 6

lagrange trust me

Answer 7

that is why you need logarithmic differentiation

Answer 8

but thank you everyone, my Homework is complete

Answer 9

oh really, i satellite wrong?

Answer 10

is*

Answer 11

ya, he didnt realize it is a product rule question

Answer 12

lol

Answer 13

make the first time f and the second g, the rule is f ' g + f g ' = derivative of f*g

Answer 14

term*

Answer 15

you can also write it as
\[e^{\ln(3x\times 4x)}\] and use the chain rule

Answer 16

oh, satellite how could you forget this was a product rule problem

Answer 17

ya but he won't know that

Answer 18

how did you not realize it was too, it is your homework no? so i would assume you just learned it?