1/6-2/3m> 1/4 1/6-2/3m> 1/4 @Mathematics
-8<m<0
multiply everything by 3m 3m/6-6m/3m>3m/4 m/2-2>3m/4 multiple everything by 4 2m-8>3m -8>m
\[\frac{1}{6}-\frac{2}{3}m>\frac{1}{4}\] multiply by 12 to get \[2-8m>3\] add 8m get \[2>8m+3\] subtract 3 get \[-1>8m\] divide by 8 get \[-\frac{1}{8}>m\]
really getting some random answers this evening
i don't see where i went wrong
@satellite73 I know right :P @da1bearsfan I don't even know what I am doing..
@satellite73 how did u get multiply by 12 though?
is the question: \[\frac{1}{6}-\frac{2}{3m}>\frac{1}{4}\] OR \[\frac{1}{6}-\frac{2}{3}m>\frac{1}{4}\] in the first case, my answer is correct, and in the latter satellite is.
you cannot multiply by 3m because you don't know whether it is positive or negative
@ nico i multiplied by 12 so i didn't have to work with the fractions. you don't need to do that if you don't want
Ohh ok now i know my teacher never explained that to me
btw it really was \[\frac{1}{6}-\frac{2}{3}m>\frac{1}{4}\] right?
yes it was satellite
you can subtract \[\frac{1}{6} \] if you want and get \[-\frac{2}{3}m>\frac{1}{4}-\frac{1}{6}\] \[-\frac{2}{3}m>\frac{1}{12}\] \[m<\frac{1}{12}\times -\frac{3}{2}\] \[m<-\frac{1}{8}\]
when you multiply both sides by a negative number you have to switch the inequality. i find it easier to work without the fractions, that is why i multiplied EVERYTHING by 12
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