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let f(x)=1-2x^2 and g(x) = x+1 compute the following (f o f)(x)
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do you mean (f o g)(x) ???
yes
do I time the f(x) twice
\[f\circ f(x)=f(f(x))=f(1-2x^2)=1-2(1-2x^2)^2\]
satellite he meant f o g not f o f
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no I mean f 0 f that is correct
oh then satellite has it
ok thanks
so if i have (g o g) do I go like this
but use the formula for g?
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to find gog, substitute x with the equation of g in the formula of g. gog=g(g(x))=g(x+1)=(x+1)+1=x+2
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