Question

Find the Critical points of the function:
f(x)= 2x^3+x^2+2x

Answer 1

solve it as
2x^3+x^2+2x=0
and find x

Answer 2

I think i'm supposed to take the derivative of the function first, before I find x.

Answer 3

do they give you a domain?

Answer 4

no

Answer 5

okay. i know how to do these! i just reviewed them today!

Answer 6

f'(x) = 6x^2 + 2x + 2

Are you finding the Turning Point ?
I don't get what critical point means =/

Answer 7

find the derivative, then see where x is limited. so like what x cannot equal, those are the critical points.

Answer 8

thats where i am stuck. the derivative is 6x^2+2x+2 but then i don't know how to solve for x here

Answer 9

I'm just messing up on the simple algebra at the end

Answer 10

critical points....take the first derivatice and set it to zero which mimi did. just do some subtracting and dividnt and you will get your crit points.
Extrema occure around crit pnts

Answer 11

i don't think there are any critical points

Answer 12

yes there is

Answer 13

you have to use quadtratic formula or complete the square to find your roots

Answer 14

oh okay that explains it, thanks you

Answer 15

thank you*

Answer 16

that is a parabola so there is a minima

Answer 17

w8, does the critical point mean the turning point ?

Answer 18

Also looking at the graph of this... there are no x intercepts so that will save you some trouble

Answer 19

critical points are where d/dx=0 or d/dx=dne

Answer 20

if f'(c)=0 or it is not differntiable at c then c is a critical number of f

Answer 21

oooohh. i got it.

Answer 22

Oh okay, then its the turning point then xD