Question

I have Synthetic division for my problem, yet it won't go back to the original factors, x = 10, x = 6 and x = 2. I have no clue what went wrong, I was able to find x = 10 but the starting equation was x^3 - 12x^2 + 32x 120. I have Synthetic division for my problem, yet it won't go back to the original factors, x = 10, x = 6 and x = 2. I have no clue what went wrong, I was able to find x = 10 but the starting equation was x^3 - 12x^2 + 32x 120. @Mathematics

Answer 1

what is sign between 32x and 120

Answer 2

opps its suppose to be -

Answer 3

x^3 - 12x^2 + 32x-120=0, have 3 solutions two of them are imaginary
{x -> 5/3}, {x -> 2 - i}, {x -> 2 + i}

Answer 4

How did you get 5/3 I got (x - 10) and how did you get the complex numbers?

Answer 5

the equation is not complete, please check again

Answer 6

How is it not complete?

Answer 7

x^3 - 12x^2 + 32x 120
-> x^3 - 12x^2 + 32x(- or +)120

Answer 8

Oh x^3 - 12x^2 + 32x - 120

Answer 9

That equation have 3 solution 1 real, and the other imaginary

Answer 10

Ok but how would I solve for it. Cause from synthetic division i got 10 remember?

Answer 11

Sorry my answer not corect. I'll calculate again

Answer 12

the solution {x -> 10}, {x -> 1 - i Sqrt[11]}, {x -> 1 + i Sqrt[11]}

Answer 13

Haha its ok, how did you get 1 - i√11, I got 1 ± 2√11

Answer 14

Ok I was able to get 1 ± 2i√11

Answer 15

Ok i got 1 ± i√11 wow Im doing horrible today..

Answer 16

lol, ok you found it

Answer 17

Yeah haha, I just messed up tremendously, so it would be x = 1 ± i√11

Answer 18

sure