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Mathematics 19 Online
OpenStudy (anonymous):

A road running north to south crosses a road going east to west at the point P. Car A is driving north along the first road, and car B is driving east along the second road. At a particular time car A is 10 kilometers to the north of P and traveling at 80 km/hr, while car B is 15 kilometers to the east of P and traveling at 100 km/hr. How fast is the distance between the two cars changing?

OpenStudy (anonymous):

the answer is 460/radical(13). I just don't know how to get there?

OpenStudy (anonymous):

wt do u mean by radicals........is it in terms of angles u tell me where u got it

OpenStudy (anonymous):

460/radicalsign(13) km/h. They give us the answers so we can check our work but we need to show how we get to the answer.

OpenStudy (anonymous):

Dt[d] = 460/Sqrt[13] = 127.581

OpenStudy (anonymous):

yes thats the answer in km/h

OpenStudy (anonymous):

do u have any formula for such kind of problems

OpenStudy (anonymous):

no thats why I need help on here

OpenStudy (anonymous):

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