OpenStudy (anonymous):

how do you find the integral from 1/2 to 1 of (y+4)/(y^2+y) dy ??

6 years ago
OpenStudy (anonymous):

\[\int\limits_{1/2}^{1}(y+4)/(y^2+y)dy\]

6 years ago
OpenStudy (anonymous):

i started by using the partial fractions method, but got kinda stuck towards the end...

6 years ago
OpenStudy (anonymous):

nevermind, i got it, it was 1.909542505 or 4ln(1/2)-3[ln(2)-ln(3/2)]

6 years ago