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OpenStudy (anonymous):
how do you find the integral from 1/2 to 1 of (y+4)/(y^2+y) dy ??
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OpenStudy (anonymous):
\[\int\limits_{1/2}^{1}(y+4)/(y^2+y)dy\]
OpenStudy (anonymous):
i started by using the partial fractions method, but got kinda stuck towards the end...
OpenStudy (anonymous):
nevermind, i got it, it was 1.909542505 or 4ln(1/2)-3[ln(2)-ln(3/2)]
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