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Mathematics 42 Online
OpenStudy (anonymous):

Find the volume of the pyramid.

OpenStudy (anonymous):

|dw:1319592059542:dw|

OpenStudy (radar):

This appears as a rectangular pyramid with a rectangle base 12 x 5 ft. Now is the 15 ft dimension the altitude of the pyramid or the face distance (the distance from the base bottom to the top along the side (not perpendicular to the bottom of the structure)

OpenStudy (radar):

if it is the altitude then the volume is equal to 1/3 the base area times the height. or Volume (V)=1/3 (5 X 12 X 15) = 300 cubic feet.

OpenStudy (radar):

If the 15 is the slant height of a wall then there is some extra calculating required.

OpenStudy (anonymous):

The answer actually comes out to be 150ft cube

OpenStudy (anonymous):

15' is the slant height

OpenStudy (anonymous):

My drawing is not that good

OpenStudy (radar):

If it is the slant height, we then need to calculate the altitude (h) for that we need to use the pyhgaorem (or however you spell it). Can't quite get that to work, still get a value over 200 cubic ft. Guess I am messing up somewhere.

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