Question

solve each 1st degree equations with radicals

(square root of x-8)=2

Answer 1

\[\sqrt{x-8} =2\]

Answer 2

simple square both sides

Answer 3

\[x-2 = 2^2\]

Answer 4

Square both sides to get rid of the radical \[(\sqrt{x-8})^2 = 2^2\] Squaring a radical cancels out the radical leaving you with \[x - 8 = 4\] Solve for x \[x = 12\]