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OpenStudy (anonymous):
I need to find any critical numbers of the function: h(x)=sin^2 x + cos x and 0
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OpenStudy (anonymous):
find the first derivative and set it =0 :)
OpenStudy (anonymous):
lol i got that. it was the finding the derivative part that sucks.
OpenStudy (anonymous):
h(x)=sin^2 x + cos x and 0<2pii Dh(x)=D(sin^2 x + cos x) =Dsin^2 x + Dcos x let u=sinx so that Du^2=2uDu therefore =2sin x cosx -sinx=sin 2x -sinx
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