Question

I need to find any critical numbers of the function: h(x)=sin^2 x + cos x and 0 14 years ago

Answer 1

find the first derivative and set it =0 :)

Answer 2

lol i got that. it was the finding the derivative part that sucks.

Answer 3

h(x)=sin^2 x + cos x and 0<2pii
Dh(x)=D(sin^2 x + cos x) =Dsin^2 x + Dcos x
let u=sinx so that Du^2=2uDu therefore
=2sin x cosx -sinx=sin 2x -sinx