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Mathematics 20 Online
OpenStudy (anonymous):

help solve this

OpenStudy (anonymous):

hey did u got the solution

OpenStudy (anonymous):

not yet i lost are chat

OpenStudy (anonymous):

say

OpenStudy (anonymous):

x^1/2 x ^3

OpenStudy (anonymous):

im stuck here

OpenStudy (anonymous):

hmmm it means\[x^{\frac{1}{2}+3} = x^{\frac{1+6}{2}} = x^\frac{7}{2}\]

OpenStudy (anonymous):

\[128x^{^{-3}}=\sqrt{x}\]

OpenStudy (anonymous):

now this wud help u

OpenStudy (anonymous):

let me try

OpenStudy (anonymous):

so what we had \[128 = x^\frac{7}{2}\] \[128 = 2^7 = x^\frac{7}{2}\] \[2 = x^\frac{1}{2}\] so, \[x = 2^2 = 4\]

OpenStudy (anonymous):

hence we had x = 4

OpenStudy (anonymous):

\[128x^{-3} = x ^{1/2}\] \[128 = x ^{7/2}\]

OpenStudy (anonymous):

2 to the power of seven is 128

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

remove the seven fomthe right hand side and we got

OpenStudy (anonymous):

we square the 2 which gives us 4

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