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hey did u got the solution
not yet i lost are chat
say
x^1/2 x ^3
im stuck here
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hmmm it means\[x^{\frac{1}{2}+3} = x^{\frac{1+6}{2}} = x^\frac{7}{2}\]
\[128x^{^{-3}}=\sqrt{x}\]
now this wud help u
let me try
so what we had \[128 = x^\frac{7}{2}\] \[128 = 2^7 = x^\frac{7}{2}\] \[2 = x^\frac{1}{2}\] so, \[x = 2^2 = 4\]
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hence we had x = 4
\[128x^{-3} = x ^{1/2}\] \[128 = x ^{7/2}\]
2 to the power of seven is 128
yes
remove the seven fomthe right hand side and we got
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we square the 2 which gives us 4
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