Question

A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 50 meters high with an initial upward speed of 30 meters per second, what will its height be after 2 seconds?

h+vt-4.9t^2
Where h = 50
v = 30
t = 2
whats the Answer?

Answer 1

h=50 v=30 t=2
Plug these numbers in the equation and you have the solution

Answer 2

so would it be 50+302-4.92^2

Answer 3

50+30*2-4.9*2^2

Answer 4

is the answer 620.4?