Question

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?


y= -
2y= -3x+ 7
2x+ 3y- 7 = 0

wich answer is it

Answer 1

it is the 1st answer

Answer 2

because 5-(-1)/-1-(3)=-3/2 answer 2 th :)

Answer 3

slope =-3/2

Answer 4

you got it

Answer 5

because 5-(-1)/-1-(3)=-3/2 answer 2nd :)

Answer 6

A line passing through two points can be represented in the slope-intercept form as y = mx + b. Where m is the slope and b is the y intercept. But, first we need to find the slope. Slope = difference in y coordinates of the two given points / difference in x coordinates of the two given points. In this case, slope = (-1-5)/(3-(-1)) = -6/4 = -3/2. So, the equation is y = -3x/2 + b. To find b, we should use one of the points on the line (any one of the two really) and plug values for y and x. Let us pick the point (3, -1). We get: -1 = -3(3)/2 + b -1 = -9/2 + b => b = 9/2 - 1 = 7/2 So, the equation is: y = -3x/2 + 7/2

Answer 7

my answer is true ? :)

Answer 8

so it is the 1st answer not the 2nd

Answer 9

hoblos - you getting it right is great. but, helping the others understand to get it is the important thing.