Beams for holding a sprinkler system are to be placed across the top of the greenhouse. The formula for the height h at which the beams are to be placed is given by.... Beams for holding a sprinkler system are to be placed across the top of the greenhouse. The formula for the height h at which the beams are to be placed is given by.... @Mathematics
\[h=\sqrt{15^{2-}(a/2)^{2}}\]
hey dint u figured it out??
No i got stuck after i got 225-(a/2?^2)
h^2 = 225 - a^2/4 => h^2 = (900 - a^2)/4 = [30^2 - a^2]/4 => h^2 = (30-a)(30+a)/4 => h = [(30^2-a^2)^(1/2)]/2
Where did you get 900 from?
\[h = \frac{\sqrt{30^2 - a^2}}{2}\]
You set the problem up wrong I think. It looks like this on the paper... \[h=\sqrt{r ^{2}-(a/2)^{2}}\] ...... and r=15
\[h = \sqrt{225 - \frac{a^2}{4}} = \sqrt{\frac{225 \times 4 - a^2}{4}} = \sqrt{\frac{900-a^2}{4}} = \frac{\sqrt{30^2 - a^2}}{2}\]
\[r^2 = 15^2 = 15 \times 15 = 225\]
now see these and say whether i set the wrong formulae??
Ok so where do i go from there to solve for h
if u will know the value of a then only u can solve it for h!!!
a=25
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