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If f(x) = x +2, all over 2, then what is f^–1(x)
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Assuming this an inverse function, the first step you would take is switching x and ys, then solving for y again.
First write \[y = \dfrac{x+2}{2}\] Now swap the x and y. \[x = \dfrac{y+2}{2}\] Now solve for y
The reason we "swap the x and y" is because the inverse of a function is a reflection about the line y = x. ( so wherever we see y, we switch it with x and vice versa.)
so you get 2y = x?
2y-2 = x*
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