An unstretched elastic spring has a mass M = 2.13 kg and a length of l0 = 0.605 m. The spring has a uniform linear mass density. When placed in the vertical position and supported at the higher end, the spring stretches due to its own weight by 59.5%. What is the elastic potential energy of the spring? An unstretched elastic spring has a mass M = 2.13 kg and a length of l0 = 0.605 m. The spring has a uniform linear mass density. When placed in the vertical position and supported at the higher end, the spring stretches due to its own weight by 59.5%. What is the elastic potential energy of the spring? @Physics

Question

anonymous · Answer

$$u=.5k\times\Delta l^2$$
$$k=F/\Delta l $$ $$k=mg/\Delta l$$ $$\Delta l=.605\times.595=.36$$ 
$$u=.5(mg/\Delta l)\Delta l^2$$ $$u=.5mg \times \Delta l$$
$$u=.5(2,13\times 9,98)\times ,36$$ $$u=3,83J$$

anonymous · Answer

u= potential energy
k= spring constant

anonymous · Answer

PE = mgh 
= 2.13 x 9.81 x (0.605 x 0.595)
= 7.521 J

anonymous · Answer

Sorry, I meant g=9,8

$$u=3,76J$$