Question

f(x) = 3/1+2e^-5x
Find f`(x) and f"(x)

Answer 1

do you know the quotient or product rule?

Answer 2

yes but I don`t seem to get the right answer!

Answer 3

which one you prefer to use?

Answer 4

The quotient rule

Answer 5

ok let
h(x)=3
and g(x) = 1+2e^-5x

\[\large{f'(x)=\frac{h'(x)g(x)-h(x)g'(x)}{g(x)^2}}\]

Answer 6

so
\[\large{f'(x)= \frac{ (0 \times -1+2e^{-5x}) - 3 \times(-10e^{-5x}}{(1+2e^{-5x})^2}}\]

Answer 7

\[=\large{\frac{30e^{-5x}}{(1+2e^{-5x})^2}}\]

Answer 8

for the second derivative, u do the same....try doing it and if u get stuck ill help u

Answer 9

lalaly how did you get a -1 and a -3?

Answer 10

shouldn't it have been 0 x 1+2e^-5x in the numerator?

Answer 11

ignore the -1 that got there by mistake

Answer 12

ok thanks

Answer 13

ignore the negative sign only not the 1

Answer 14

yeah I get it