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how to solve arctan[tan(7pi /4)]
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7pi/4
atan and tan are inverse functions
but why tan (7pi/4) =-1
so you can simplify 7pi/4 and write that 7pi/4=-pi/4 or 3pi/4
yes tan and arctan are inverse of each other
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so the answer will change ?!!
no, it will still be -pi/4
find a place on the unit circle in the interval \[[-\frac{\pi}{2},\frac{\pi}{2}]\] where the tangent is also -1
\[\tan(\frac{7\pi}{4})=\frac{\sin(\frac{7\pi}{4})}{\cos(\frac{7\pi}{4})}=-1\]
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