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Mathematics 17 Online
OpenStudy (anonymous):

can somebody solve this

OpenStudy (anonymous):

wht?

OpenStudy (anonymous):

\[3^{3x+1}=9^{x-1}\]

OpenStudy (anonymous):

hi simon how u doin?

OpenStudy (anonymous):

not bad m8

OpenStudy (anonymous):

yourself

OpenStudy (anonymous):

stuck on this equation

OpenStudy (anonymous):

\[3^{2x+1} = 3^{2(x-1)}\]

OpenStudy (anonymous):

see here we have common base on both the sides so equate the powers \[2x + 1 = 2 \times (x - 1)\] then solve it for x

OpenStudy (anonymous):

what does equate mean

OpenStudy (anonymous):

means as base is same so the powers will be equal

OpenStudy (anonymous):

look at the equation i wrot its 3^3x+1

OpenStudy (anonymous):

no it will be \[9^{x-1} = 3^{2 \times (x-1)} = 3^{2x-2}\]

OpenStudy (anonymous):

oh so sorry so in that case \[3x + 1 = 2x - 2\]

OpenStudy (anonymous):

i got that bit so i add 2x and 3x

OpenStudy (anonymous):

\[3x - 2x = -1 - 2 \] \[x = -3\]

OpenStudy (anonymous):

yes i see now thank you my friend

OpenStudy (anonymous):

did you add me on facebook

OpenStudy (anonymous):

did u receieved my request

OpenStudy (anonymous):

i havnt recieved it yet

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