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can somebody solve this
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wht?
\[3^{3x+1}=9^{x-1}\]
hi simon how u doin?
not bad m8
yourself
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stuck on this equation
\[3^{2x+1} = 3^{2(x-1)}\]
see here we have common base on both the sides so equate the powers \[2x + 1 = 2 \times (x - 1)\] then solve it for x
what does equate mean
means as base is same so the powers will be equal
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look at the equation i wrot its 3^3x+1
no it will be \[9^{x-1} = 3^{2 \times (x-1)} = 3^{2x-2}\]
oh so sorry so in that case \[3x + 1 = 2x - 2\]
i got that bit so i add 2x and 3x
\[3x - 2x = -1 - 2 \] \[x = -3\]
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yes i see now thank you my friend
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