Question

f(x)=((1)/(5))(x+9)^2+8

find the vertex

Answer 1

Equation \[f(x)=1/5(x+9)^{2}+8\]=\[1/5x^2+18/5x+121/5\]
= \[ax^2+bx+c\]
Therefore, a=1/5 b=18/5 c=121/5

And you can find the X-Axis of the Vertex x=-b/2a=-(18/5)/(2/5)=-9

VERTEX=(-9,8)

Answer 2

Thanks for explaining :)