Find the derivative of the function below.
\[\frac{2 - \ln(x)}{12^{\frac{3}{2}}}\]
the denominator should say \[12x^{\frac{3}{2}}\]
I was just about to say :)
Ive gotten to a cetain point.. but im stuck on the simplifying
certain*
did u use quotient rule?
yeah
Post what you have so far and I'll see if you're close.
du/dx = -1/x dv/x = 18 x^(1/2)
\[\frac{(12x^{\frac{3}{2}})(-\frac{1}{x}) - \frac{3}{2}(12)x^{\frac{1}{2}}(2 - \ln(x)}{(12x^{\frac{3}{2}})^2}\]
\[{(12x^{3/2})(-1/x)-18x^{1/2}(2-\ln x) \over 12^2x^3}={-48x^{1/2}+18x^{1/2}\ln x \over144x^3}\]
\[-1/(12*x^(5/2))-(1/8)*(2-ln(x))/x^(5/2)\] that's what maple gave me.
not much left here... factor out 6x^(1/2) \[{3\ln x-8 \over 24x^{5/2}}\]
ok..on the first one you posted.. where did the 48^1/2 come from??
notice how 12x^(3/2)(-1/x)=-12x^(1/2) and 2(-18x^(1/2)=-36x^(1/2) we added those x^1/2 terms in the numerator to get -48x^(1/2)
ah ok
Thank you Turing!!
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