You invest $6000 in two account paying 6% and 9% annual interest. At the end of the year, the account earn the same interest. How much was invest at each rate?
P(1+.06) = P(1+.09) solve
x + y = 6000 .06x = .09y
x + y = 6000 .06x - .09y = 0 (multiply by 100)
x + y = 6000 6x - 9y = 0
9(x + y = 6000) 6x - 9y = 0 9x + 9y = 54000 6x - 9y = 0
15x = 54000 x = 3600
y = 2400
So $3600 at 6% and $2400 at 9%
(Thanks, blexting and indy25, I also have another problem) The manager of a Starbuck store plans to mix A-grade coffee that cost $9.50per pound with B-grade coffee that costs $7.00per pound to create a 20-pound blend that will sell for $8.50 per pound. How many pounds of each type of coffee are required?
lol, I would put in 20 lbs of $7/pound
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