Question

factor the quadratic expression completely, and find the roots of the expression.



1. 66x^2 - 130x + 56


2. 26x^2 - 159x - 65

Answer 1

lol

Answer 2

\[2\cdot 33x^2-2 \cdot 65x+2 \cdot 28\]
each term has a two in common

Answer 3

I've been working on these problems for 24 hrs.

Answer 4

\[2(33x^2-65x+28)\]

Answer 5

Supaman -- what are you finding difficult about these problems? Where do you get stuck?

Answer 6

the answer i got is 2(11x7)(3x-4)

Answer 7

now wonder. i would cheat
of course that will not help on a test. myininaya has a nice method. maybe will share
http://www.wolframalpha.com/input/?i=66x%5E2+-+130x+%2B+56+

Answer 8

im trying to see if my answer is right.

if so how the heck do i do the root

Answer 9

that's the answer: 2(11x-7)(3x-4)

Answer 10

that web site i so dont understand.

Answer 11

now see if you factor \[33x^2-65x+28\]
by finding two factors of 33(28) that have product 33(28) and sum -65
so
33(28)=66(14)=22(42)=44(21)=-44(-21)

Answer 12

-65=-44-21

Answer 13

-65x=-44x-21x

Answer 14

33x^2-44x-21x+28

Answer 15

um? im lost sir. like i said i got 2(11x7(3x-4) is that right or not?

Answer 16

yes

Answer 17

\[11x(3x-4)-7(3x-4)=(3x-4)(11x-7)\]

Answer 18

your answer is right

Answer 19

but don't forget about the 2
2(3x-4)(11x-7)

Answer 20

JESUS! so how do i finish? it thats where im left off at.

Answer 21

that is it, you are done

Answer 22

yeah

Answer 23

you just have to find the roots

Answer 24

so thats the root too?

Answer 25

do you know the definition of a root?

Answer 26

yea thats what i was wondering how to do.

Answer 27

find the roots by finding where the expression is 0

Answer 28

graphically, a root is where the function crosses the x axis.

Answer 29

Quick question Supaman -- can you expand these binomials?

(x-3)(x+4) =

(2x + 3)(4x-1) =

(4x -2)(7x+3) =

Answer 30

nope i hate3 math im failing and im on my last week in college.. math is a subject i can never use or do.

Answer 31

i dont know what that means mathteacher.

Answer 32

hes asking if you know how to multiply binomials

Answer 33

>i dont know what that means mathteacher.

Ok, that makes sense then. You have to go and learn how to multiply binomials before you can learn to factor them.

As for math not being useful in life... managing your own money is all about math. (not necessarily factoring polynomials though...) :-p

Answer 34

Here is Paul's Online Math Notes, which feature very nicely written explanations of all sorts of math topics.

This is their Factoring Polynomials lesson:
http://tutorial.math.lamar.edu/Classes/Alg/Factoring.aspx

Answer 35

right. so, how do i finish this??

Answer 36

didn't you already finish the first one?

Answer 37

2(3x-4)(11x-7)

Answer 38

yes, but i thought i have to root, and @teacher can't open that link it says some off stuff.

Answer 39

yes just find where the expression is 0 to find the roots

Answer 40

The problems you posed here are advanced polynomial factoring.

First, you have to learn how to add, subtract and multiply polynomials: http://tutorial.math.lamar.edu/Classes/Alg/Polynomials.aspx

Then after that, learn how to factor them:
http://tutorial.math.lamar.edu/Classes/Alg/Factoring.aspx

After those two lessons, you should be ready to try the problems you posted here.

Answer 41

2(0)(11x-7)=0
so when 3x-4=0 we have a root
2(3x-4)(0)=0
so when 11x-7=0 we have a root

Answer 42

do i 2(11(0))(3(0)-4)