Question

Eric can paint a wall in 20 minutes. His brother, Jessup, can paint the same wall in 30 minutes. How long will it take them working together to paint the wall?

Answer 1

y=2/3x where y = the time it takes eric

Answer 2

\[\frac{20\times 30}{20+30}\]

Answer 3

why?

Answer 4

Do you speak spanish??

Answer 5

no

Answer 6

Eric 1 wall - 20 minutes
X xall - 1 minute

Answer 7

then X = 1/20 wall

Answer 8

the same forJessus

Answer 9

Jessus : Y=1/30 wall

Answer 10

in one minute
so if they work together, you just have to....(i don't know the word) add? X+Y

Answer 11

and that´s waht they both do in one minute

Answer 12

why is a good question. lets work it out.
the entire job is one job,
eric does
\[\frac{1}{20}\] per minute and his friend does
\[\frac{1}{30}\] per minute so their combined rate is
\[\frac{20+30}{20\times 30}\] and you want to solve
\[\frac{20+30}{20\times 30}T = 1\] and therefore you get
\[T=\frac{20\times 30}{20+30}\] and now you never have to do it again

Answer 13

i need help with my homework.

Answer 14

erick does the job in x hours, joe does it in y hours their combined rate is
\[\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}\] and therefore the job gets finished by solving
\[\frac{x+y}{xy}T = 1 \] thus
\[T=\frac{xy}{x+y}\]

Answer 15

thank yall.