Question

Please help! How do I write an expression that represents the area of the triangle in terms of x? (Diagram included)

Answer 1

A triangle has the base: 2x+1/4 and height: x-3/2

Answer 2

area of a triangle is formulaicly solved bh/2

Answer 3

I tried this:

A = 1/2bh
=1/2 (2x+1/4)(x-3/2)
=1/2 (2x+1/4)(x-4(2)/2(2))
=1/2 (2x+1/4)(2x-6/4)
=1/2 (4x^2-12x+2x-6/4)
=1/2 (4x^2-10x-6/4)
=2x^2-5x-3/4
=(2x+1)(x-3)/4

But the answer is (2x+1)(x-3)/16

Answer 4

I don't know why the denominator is 16...

Answer 5

2*8=16

Answer 6

it's not 1/2*4?

Answer 7

when you multiply the base times height, you get a denominator of 8, then you multiply the expression by 1/2, which gives a denominator of 16

Answer 8

what do you mean?

Answer 9

no it's not because it needs to become: (2x+3)(x-3)

Answer 10

/16

Answer 11

Estudntelivre , very nice explanation. +1 :)

Answer 12

Sorry, Let's try again.
I think it would be expressed better like this:
=[(2x+1)/4][(x-3)/2]1/2
=[(2x+1)/4][(2x-6)/4]1/2
=[(2x+1)(2x-6)/16]1/2
=[(4x^2-10x-6)/16]1/2
=[(2x^2-5x-3)/8]1/2
=(2x+1)(x-3)/16

Voilá

Answer 13

:O Thank you so much!!

Answer 14

There is another way, I think.
=[(2x+1)/4][(x-3)/2]1/2
=[(2x+1)(x-3)/8]1/2
=(2x^2-5x-3)/16
=(2x+1)(x-3)/16