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Use the distance formula. P(-2, 7) and Q(-6, 4)
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When u know the formula, simply use it.
5
@saifoo.khan im trying to see if im correct, because my answer was \[\sqrt{-11}\]
formula sqr root of [ (xsub2-xsub1)^2+(ysub2-ysub1)^2 ] same for 3 dimensions except you include the variable z sqr root of [ (xsub2-xsub1)^2+(ysub2-ysub1)^2 +(zsub2-zsub1)^2]
i could be wrong, havent looked to see
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P(-2, 7) and Q(-6, 4) d=√((x^2-x^1 )+(y^2-y^1 ) ) =√([-6-(-2) ]+(4-7)) =√(-8+3) =√(-5) =5 kk i see what i did wrong now.
over 4, down 3 pythagoras says it is \[d^2=3^2+4^2=25\implies d = 5\]
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