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Choose the equation that could be used to find two consecutive integers whose sum is 67. Answer n + (n + 1) = 67 n - (n + 1) = 67 n + (n + 2) = 67 n + n = 67 Choose the equation that could be used to find two consecutive integers whose sum is 67. Answer n + (n + 1) = 67 n - (n + 1) = 67 n + (n + 2) = 67 n + n = 67 @Mathematics
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n + (n + 1) = 67
ida used 67/2
first one
"that could be used" ... first and last seem to be on the board to me
33+33 = 66 34+34 = 68 seems to me that it could then be 33 and 34 to average the 2 lol
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\[ n + (n + 1) = 67 \Rightarrow 2n+1=67 \Rightarrow n=33 \] so the two consecutive numbers are 33 and 34.
first is right because n+n+1=67 on solving gives 33 so 33 and 34
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