Question

how to factor 5x^2-32x-21=0

Answer 1

It's factorable, but not in the way that you're used to doing it

Answer 2

Solve for the roots of the quadratic.

Answer 3

ok and how exactly you do that

Answer 4

I'll post the steps

Answer 5

Quadratic equations take the form:
\[\Large ax{^2} + bx + c = 0\]
Use the quadratic formula to find its roots:
\[\Large \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]

Answer 6

well I need to use a factoring way not a quadratic way, I already know how to do it by the qudratic form

Answer 7

5x^2-32x-21=0
5x^2+3x - 35x - 21 = 0
x(5x+3)-7(5x+3) = 0
(5x+3)(x-7) = 0
x = 7, -3/5

Answer 8

I don't get the second line

Answer 9

-32 = -35+3

Answer 10

Split the middle term into 3 and -35

adds to get -32
multiplies to get -105

Answer 11

ok

Answer 12

-105 is what you get when you multiply a*c or 5*-21

Answer 13

I don't get how you did the 3rd line