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find the second derivative f(x) = e^(-x^2/2) find the second derivative f(x) = e^(-x^2/2) @Mathematics
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\[f'(x)=(\frac{-x^2}{2})'e^{\frac{-x^2}{2}}\]
\[e^{-x ^{2}/2}\]
second derivative?
find the derivative of the first derivative
\[f''(x)=(\frac{-x^2}{2})''e^{\frac{-x^2}{2}}+(\frac{-x^2}{2})'(\frac{-x^2}{2})'e^{\frac{-x^2}{2}}\]
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alright now I have to set that equal to zero and solve for x
why? you are trying to find second derivative are you looking for inflection points?
Second derivative e^(-x^2/2) *(x^2 - 1)
the interval on which the graph is concave up and concave down and inflection points
try this http://www.wolframalpha.com/widgets/view.jsp?id=c44e503833b64e9f27197a484f4257c0
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