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Chemistry 21 Online
OpenStudy (anonymous):

Calculate the mass of each substance from the number of moles given. 0.819 mol manganese(IV) oxide

OpenStudy (kociela):

well, this is other way around. First mass from m = n x M , molar mass as summing element's molar masses from periodic table ---> \[mass = percent of molar mass \times mass,m\] and for each element percent of molar mass is the element's molar mass in molecule divided by molar mass, M

OpenStudy (anonymous):

wait this is kinda of confusing

OpenStudy (kociela):

what part ?

OpenStudy (kociela):

percent of molar mass -meant-> ratio of molar masses.

OpenStudy (anonymous):

I am confused in plugging in

OpenStudy (kociela):

could you be more specific X.^ http://www.webelements.com/

OpenStudy (anonymous):

Actually I am really confused about the whole problem. I mean I think I need help step by step.

OpenStudy (kociela):

ok. molar masses: MgO2 beacause oxygen have 2 electron less from stable 8 and Mg(IV) --> Mg 24,3 g/mol and O 16,0 g/mol safe and sound, always as that XD specific is 15,999... --> so if whole molar mass is 24,3 + 2 x 16,0 = 56,3 g/mol --> ................. ok :P , did the calculation and you don't need that way necessarily so by the formula you have 2 oxygen and 1 magnesium in in one molecule, so what is the mass of 0,819 mol of manganese and how that molar amount change for oxygen ?

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