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if f(x)= x^4 - 4x evaluate lim x->-1 (f(x)-f(-1))/(x+1) a. -8 b. 0 c. 1 d. 2 e. 4 PLEASE HELP!
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it is -8. By first principle,f'(-1)=lim h->0 (f[-1+h]-f[-1])/h
this is \[\lim_{x\rightarrow -1}\frac{f(x)-f(-1)}{x+1}\]?
\[f(-1)=5\] so you get \[\frac{x^4-4x-5}{x+1}=\frac{(x+1) (x^3-x^2+x-5)}{x+1}\]
cancel and replace x b y -1 to get your answer
steps clear?
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are you sure thats factored right??
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