Question

can some one solve it f(x) = arctanx/x....f`(0) = ? can some one solve it f(x) = arctanx/x....f`(0) = ? @Mathematics

Answer 1

so arctanx/x is basically tan inverse/x

Answer 2

yeah

Answer 3

so do it that way

Answer 4

i have got 0...but im not sure if its correct or not

Answer 5

whats your value for x that you plugged in?

Answer 6

f`(0) = ?

Answer 7

help me with this, how do i differentiate sin(\[\cos(\pi t/4)\]

Answer 8

yes that is the right answer for you

Answer 9

(sin(cos(pi*t/4))` = cos ( cos(pi*t/4)*(-sin(pi*t/4)

Answer 10

differentiate sin(cos(πt/4), let u=cos(πt/4)
Dsinu=(cosu)D(cos(πt/4)
=(cosu)(-sin(πt/4)(pi/4)Dt

Answer 11

thats right

Answer 12

=(cos(cos(πt/4) ))(-sin(πt/4)(pi/4)Dt

Answer 13

i got the question wrong, its actually only \[\cos (pit/4) oops\]