Question

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Answer 1

\[\sqrt{x}=6\sqrt{y}\]
\[\frac{1}{2\sqrt{x}}=\frac{3}{\sqrt{y}}y'\] solve for
\[y'\]

Answer 2

\[\sqrt{x}=6\sqrt{y}\] Wouldn't you solve the equation for y, so you can differentiate with respect to x to find: \[dy \over dx\]

Answer 3

So the solution is sqrt(y)/6sqrt(x)?

Answer 4

Are you talking to satellite73?

Answer 5

To the world.

Answer 6

:) ok. just for reference, what math course is this for?

Answer 7

Calculus I. The topic is Implicit Differentiation.

Answer 8

ok cool

Answer 9

no you do not solve. that is why it says "in terms of x and y"

Answer 10

gotcha, satellite. good catch

Answer 11

i mean you do solve for y' of course and get
\[y'=\frac{\sqrt{y}}{6\sqrt{x}}\]

Answer 12

So, I was right. Thank you.

Answer 13

right. so what's going on is you take the derivative of both sides of \[\sqrt{x}=6\sqrt{y}\] with respect to x, which will give you what you put down, satellite. Right?

Answer 14

right