through a titration lab experiment, I found that after I added 23ml of NaOH (of concentration 1.0 M) to 50 ml of HCl, the thing was at the equivalent point and the ph = 7, i guess.
How do I find the initial concentration of HCL? @Mathematics

Question

through a titration lab experiment, I found that after I added 23ml of NaOH (of concentration 1.0 M)  to 50 ml of HCl, the thing was at the equivalent point and the ph = 7, i guess.
How do I find the initial concentration of HCL?   @Mathematics

anonymous · Answer

Well 7 means its basic like water.

preetha · Answer

Always write the equation: NaOH+ HCl --> NaCl + H2O
moles of NaOH = moles of HCl
Moles of NaOH = Vol x molarity = 23 ml x 1L /1000 ml x 1.00 M 
= moles of HCl = 50.0 ml x 1l/1000 ml x M (molarity of HCl)
Solve for x.