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evaluate the function at the given values of x, if possible. f(x)=7x^2-1 over x^2 a. x=3 b. x=-1 Can someone help me solve this
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\[f(3)=\frac{7\times 3^2-1}{3^2}=\frac{7\times 9-1}{9}=\frac{63-1}{9}=\frac{62}{9}\]
so that is the first one
yes. for the second one replace x by -1 still need help or you got it?
no still need help. i dont even know where to begin
:(
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where you see an x, put in the number
replace it. so for example of \[f(x)=x^2\] then \[f(3)=3^2\]and if \[f(x)=\frac{x-1}{x}\] then \[f(3)=\frac{3-1}{3}\]
in your case \[f(x)=\frac{7x^2-1}{x^2}\] so \[f(-1)=\frac{7\times (-1)^2-1}{(-1)^2}=\frac{7\times 1-1}{1}=7-1=6\]
OMG! This is such jiberish
Thanks
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