find the are of circle x2+y2=a2 by integration find the are of circle x2+y2=a2 by integration @Mathematics
bca 1 sem
bca 1 sem
ok is it related to vector analysis
yup but i m so weak in maths
i have problem with two questions and another is if the roots of the equation (a2+b2)x2-2(ac+bd)x+(c2+d2)=0 are equal, prove that a/b=c/d
can u give me solution
i will give you for the second ques in few minutes but i don't know about integration of above one
i also dont know becoz i m also from commerce stream
you also may email me at devil.magra@yahoo.com
i am writing solution of Q2 asked by u
ok
first we apply quadrattic formula
ok
mr. sumbul can u email me solutions of both questions at devil.magra@yahoo.com becoz of i will loss my train
hey i got one answer if two roots are equal, b2-4ac=0, or (-2(ac+bd))^2 - 4 (a^2 + b^2) (c^2+d^2) = 0 or 4(ac)^2 + 8abcd + 4(bd)^2 - 4(ac)^2 - 4(ad)^2 - 4(bc)^2 - 4(bd)^2 = 0 or 8abcd -4(ad)^2 -4(bc)^2 = 0 or (ad)^2 - 2(ad)(bc) + (bc)^2 = 0 or (ad - bc)^2 = 0 or ad - bc = 0 or ad = bc therefore, a/b = c/d
yes it is correct i was also typing it
do u still need solution?
yes please mail the solution of find the are of circle x2+y2=a2 by integration
ok bye thanks i give u first ur reward
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