Question

4 identical hollow cylindrical columns of steel support a big structure of mass 50,000 kg.the inner and outer radii of the columns are 30cm and 40 cm respectively . Assuming load distribution to be uniform,calculate the compressional strain of each column.

what formula should i use for this? @IIT study group

Answer 1

oh I have to revise this section! elasticity and stuff, sorry

Answer 2

its okie...:( u know youngs modulus n things lyk that??

Answer 3

Young’s modulus of steel, Y = 2 × 1011 Pa

Answer 4

Total force exerted, F = Mg = 50000 × 9.8 N

Answer 5

Stress = Force exerted on a single column =(50000*9.8)/4 =122500 N

Answer 6

Y= stress/strain

Answer 7

strain=FY/A

Answer 8

SRRY

Answer 9

strain =stress/Y

Answer 10

HERE STRESS =122500

Answer 11

Oh

Answer 12

got it

Answer 13

strain=F/AY

Answer 14

STRAIN= (122500)/[3.14*((.6)^2-(.3)^2))*2*10^11]

Answer 15

Hence, the compressional strain of each column is 7.22 × 10^–7

Answer 16

oh hw nicely done:)

Answer 17

tnank youuuu... :)

Answer 18

wlcm