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Mathematics 19 Online
OpenStudy (anonymous):

how do u prove a limit whether it exist or not??

OpenStudy (anonymous):

you must get the limit from the right and then the limit from the left, if they give the same value then the limit exist and the function is continuous

OpenStudy (anonymous):

u have to use the definition of the limit

OpenStudy (anonymous):

how do u get the limit from right n left???

OpenStudy (anonymous):

a limit is basically a tangent point when two point meet

OpenStudy (anonymous):

left limit is where the function is coming from the left right limit is when the function is coming from the right

OpenStudy (anonymous):

ill give you an example

OpenStudy (anonymous):

so let say the limit is approaching 2....i have to substitute -2 for the left side n 2 for the right side??

hero (hero):

I'm just here because a lot of people showed up

OpenStudy (anonymous):

no reply from EvrydayAzn??

OpenStudy (anonymous):

hold up it takes a long time to type

OpenStudy (anonymous):

yes it does

OpenStudy (lukecrayonz):

Graph it then check the points and see if there is any breaks o.O

OpenStudy (anonymous):

lets say their is a liner function 2x-5 and you are trying to find the limit as it approches 0

OpenStudy (anonymous):

lim f(x) = 2x-5 x->0(-) (from the left side) lim=-5 lim f(x) = 2x-5 x->0(+) (from the right side) lim= -5 they both share the same limit which means that the limit exist and thus, the function is continuous

OpenStudy (anonymous):

let say they give you 1/x-2 and the limit approaches 2....how do u show it??

OpenStudy (lukecrayonz):

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