Question

subtract 2-y/y-4 - 7y-3/4-y subtract 2-y/y-4 - 7y-3/4-y @Mathematics

Answer 1

\[{ 2-y \over y-4} - {7y-3 \over 4-y }\]is the problem?

Answer 2

yes is the answer 2/3?

Answer 3

well this is not equal to anything, so it can only be simplified:\[{ 2-y \over y-4} - {7y-3 \over 4-y }={2-y \over y-4}+{7y-3 \over y-4}={6y-1 \over y+4}\]

Answer 4

sorry should be y-4 on the bottom of the last step

Answer 5

\[{6y-1 \over y-4}\]

Answer 6

so i just add the two together? how did you figure out the y-4?

Answer 7

all I did was take the negative of the second denominator to get both the same
-(4-y)=y-4
Note this also turned the "-" sign into a "+" in the middle

Answer 8

i.e we basically multiplied the second expression by (-1/-1)

Answer 9

so would a shorter way be just to multiply by -1/-1

Answer 10

same thing

Answer 11

ok thanks. im checking my work before i turn it in.