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OpenStudy (anonymous):

(Off topic but ) How do you find Magnitude for Physics(Off topic but ) How do you find Magnitude for Physics@Mathematics

hero (hero):

Ugh, I hate magnitude and I hate physics

OpenStudy (anonymous):

ok are u using component vectors

OpenStudy (anonymous):

ijk vectors?

OpenStudy (amistre64):

magnitude is just pythag thrm for vectors

OpenStudy (anonymous):

\[R^2=\sqrt{ a^2+b^2}\]

OpenStudy (anonymous):

yeah thats right

OpenStudy (amistre64):

close, discard the ^2 from the R

OpenStudy (anonymous):

ok thanks

OpenStudy (amistre64):

spose you have a vector <3,4> the magnitude is sqrt(3^2+4^2)

OpenStudy (anonymous):

or A force of 6.0 newtons north and a force of 8.0 newtons east act concurrently on an object. The magnitude of the resultant of the two forces is

OpenStudy (anonymous):

i would still do the same thing

OpenStudy (amistre64):

yep, same thing; the forces are orthogonal to each other so they form a right triangle

OpenStudy (anonymous):

ok ty

OpenStudy (anonymous):

Help? A force of 100 newtons is applied to applied to an object at an angle of 30 degrees from the horizontal as shown in the diagram below. What is the magnitude of the vertical component of the force?

OpenStudy (anonymous):

100cos30

OpenStudy (anonymous):

=86N

OpenStudy (anonymous):

and how did you get that?

OpenStudy (anonymous):

its a formula i memorized back in highschool

OpenStudy (anonymous):

when calculating force without friction you do Force applied multiplied by cosine(theta)

OpenStudy (anonymous):

or x(cos)(theta)

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