A consulting engineer agrees to spend three days at Widgets International, three days at Doodads Incorporated and 4 days at IBM. In how many ways can she schedule her consultations?
I think this is what you mean, Let the three appointments be A, B and C. So, all possible combinations are, A B C C B A A C B B C A C A B B A C So the answer is 6.
Okay that looks good but is there any other way of figuring it out without trying to write all the combination.
I think, you could go like this, to find the combination since there is no order. Since there are 3 things, it should be 3! = 3 X2X1 = 6.
Okay that was what I thought but then I confuse myself with other steps. Thank you so much I have a big exam tomorrow morning.
http://www.mathsisfun.com/combinatorics/combinations-permutations.html This should help with the basics
Okay thank you again!
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