Question

james u thr? @Physics

Answer 1

Hi there Mr. Sunglasses

Answer 2

hiiiiiiiiii

Answer 3

wel i am back with a new topic

Answer 4

ready to help?

Answer 5

Post the question and let's see

Answer 6

before that i hav a small doubt how to find LCM AND HCF???

Answer 7

There's different algorithms. For me the easiest way is to write the numbers in their prime factorizations.

For instance, suppose we had to calculate the LCM of 36 and 10.
Well, \( 36 = 2^2 . 3^2 \) and \( 10 = 2^1 . 5^1 \). The LCM is \( 2^2 . 3^2 .5^1 = 180 \)

Answer 8

The HCF of 36 and 10 is just 2^1 = 2

Answer 9

xplain plz

Answer 10

didnt get u

Answer 11

By definition the LCM(a,b) is a multiple of both numbers, and if it is multiple of a and b, then it must be the product of all the prime factors.

That's what I did with that example:

36 = 2^2 . 3^2 . 5^0
10 = 2^1 . 3^0 . 5^1
hence
LCM(36,10) = 2^(max of 2 and 1) . 3^(max of 2 and 0) . 5^(max of 1 and 0)
= 2^2 . 3^2 . 5^1
= 4 . 9 . 5
= 180

Answer 12

HCF is the opposite.

HCF(36,10) = 2^(min of 2 and 1) . 3^(min of 2 and 0) . 5^(min of 1 and 0)
= 2^1 . 3^0 . 5^0
= 2 . 1 . 1
= 2

Answer 13

what do u mean by minimum and maximum of 2 and 1

Answer 14

max(x,y) = largest of these two numbers. So max(2,1) = 2.
min(x,y) = smallest of these two number. So min(2,1) = 1

Answer 15

wel what do i do in cases such as find lcm of PI/4 AND PI ETC

Answer 16

That's a very strange question. lcm and hcf normally only apply to integers.

Answer 17

If we now allow rational multiples of pi, then I'd say that LCM(pi, pi/4) = pi.

Answer 18

my teacher told me that lcm of pi/4 aqnd pi is pi

Answer 19

hw u got it?xplain

Answer 20

yes, there is a way to formalize this concept, but just use your intuition for that.

Answer 21

tel me i need to be fast in getting lcm any way for that?

Answer 22

If we're no longer in integers and a < b, then lcm(a,b) = b.

Answer 23

really??

Answer 24

I think it depends on context now. What are you using these LCMs for?

Answer 25

forget what I just say about lcm(a,b) for the moment.

Answer 26

like questions above

Answer 27

for example, what is LCM(pi,17)? Well, if you're allowed to multiply by 17/pi, then
LCM(pi,17) = 17. But that feels odd.

If you want to know LCM(pi,17) for the purpose of simplifying some sort of fraction, then you might say that LCM(pi,17) = 17pi.

Answer 28

So I come back and ask: why do you want to know the LCM(pi,pi/4)? As I say, it's not a standard concept to consider LCM for numbers that aren't integers (or some other special sorts of algebraic structures which needn't concern us here.)

Answer 29

actually i am studying periodic function

Answer 30

Give me the entire question/context.

Answer 31

my teacher told me that that period of sin x+cos ax is given by the lcm of the periods of individual functions

Answer 32

The period of sin x is 2pi,
the period of cos ax is 2pi/a

The sum of these functions is periodic if there exists a number T such that
sin(x+T) + cos(ax + aT) = sin x + cos ax
for all x.

Answer 33

the minimum such number T will be the period.

Well, let's experiment

Answer 34

k lets stop that

Answer 35

i hav some questions in physics

Answer 36

if a = 1, then T = 2pi
If a = 2, T = 2pi
if a = 7, T = 2pi
if a = 1/2, T = 4pi = 2 x 2pi
if a = 1/7, T = 14pi = 7 x 2pi

Answer 37

i i will post it separately

Answer 38

ok. I have to got soon; I'll do my best