Question

Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.

Question 19. Perform the indicated operations and simplify the result. Leave the answer in factored form.
@Mathematics

Answer 1

Please only i need help to finish this math work,,,

Answer 2

denominator in the second fraction is the first denominator squared...
(3x/x-1) - (x-4/x^2-2x+1) =
(3x/x-1) - (x-4/(x - 1)^2)
Thus we will need to multiply the first fraction by (x - 1) / (x - 1)...
(3x(x - 1)/(x - 1)^2) - (x-4/(x - 1)^2) and put it all over the same denominator:

[(3x(x - 1) - (x - 4)] / (x - 1)^2
Now expand the numerator and simplify...
[(3x(x - 1) - (x - 4)] / (x - 1)^2 =
(3x^2 - 3x - x + 4) / (x - 1)^2 =
(3x^2 - 4x + 4) / (x - 1)^2
Nothing more can be done with this one...that's the answer.

Answer 3

sigh

Answer 4

Nick can you keep help me?

Answer 5

asnasser please help me

Answer 6

What are the answer to question 9,10,13,17,18 and 19...

Answer 7

Iam not good for math...

Answer 8

\[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}\]first simplify numerator:
\[\frac{4}{x}+\frac{7}{x^{2}}=\frac{4x+7}{x^{2}}\]next simplify the denominator:
\[\frac{16}{x^{2}}-\frac{49}{x}=\frac{16-49x}{x^{2}}\]now use the following rule for fraction division:\[\frac{a}{b}/\frac{c}{d}=\frac{a}{b}*\frac{d}{c}\]and you will get:
\[\frac{\frac{4}{x}+\frac{7}{x^{2}}}{\frac{16}{x^{2}}-\frac{49}{x}}=\frac{4x+7}{x^{2}}/\frac{16-49x}{x^{2}}=\frac{4x+7}{x^{2}}*\frac{x^{2}}{16-49x}\]\[=\frac{4x+7}{16-49x}\]

Answer 9

The D is the right answer then...

Answer 10

Question 18?

Answer 11

for question 9, a polynomial is defined as:\[c_0x^{0}+c_1x^{1}+c_2x^{2}+...+c_nx^{n}\]
all the "c" terms are constants. it's "degree" is defined as the highest "power" of x that you have - in the case above it is a polynomial of degree "n".
e.g. 2x+9x^2 is a polynomial of degree 2.
you should be able to answer question 9 with this information.

Answer 12

ok

Answer 13

question 13 is fairly easy - you just made a simple mistake when multiplying the last terms

Answer 14

Iam sure that Question 9 the a is not the answer right...

Answer 15

Please dear, give me the answers...

Answer 16

correct - the only term given in the polynomial in question 9 is\[-2\pi\]which is just a constant. so there are no powers of x in this.

Answer 17

if it is not the a, what is the right answer?

Answer 18

Do you want a medall? please help with the answers... I do not understand math....Iam studing othe thing....but i selected elective math and it was
a wrong

Answer 19

I am not looking for a medal - I am here to try and you understand maths. If you are not interested in maths then I guess there is no point in me trying to explain it to you.

Answer 20

Ok sorry...

Answer 21

But if you know the answers... help me then with the answers...

Answer 22

Thanks dear....can i pay to you if you want... but i need answer this....

Answer 23

I can try and teach you how to solve these yourself. you may think its very complicated but it is fairly straight forward and it will give you greater satisfaction when you know that you can work these out yourself.
I am not looking for any money or medals.
Let me know if you wish to learn.

Answer 24

ok... thanks

Answer 25

Really you are right...

Answer 26

ok - good - lets start with question 9

Answer 27

Ok dear... where are you from?

Answer 28

what do you think is the "degree" of the following polynomial?\[9x-100x^{3}\]
(I live in the UK)

Answer 29

Ok i live in Sweden

Answer 30

are you thinking Sariah?

Answer 31

Yes...but it is very dificult...

Answer 32

ok - the answer here is 3 because the term with the highest power is "-100x^3".
you only need to look at the powers of x - you can completely ignore the coefficients (i.e. ignore the -100 which x^3 is multiplied by)

Answer 33

lets try one more: what is the degree of this polynomial?\[99+3x\]

Answer 34

the answer is "1" because the highest power of x here is in the term "3x".\[x = x^1\]
similarly, the polynomial:
123
has a degree of "0" because if has no "x"'s in it - just a constant.
you should now be able to answer question 9.

Answer 35

If you don´t want keep helping me, don´t worry! But thanks anyway...Really for me this assignment is dificult... you are a very good person....´couse i don,t have idea...

Answer 36

Yes you are right

Answer 37

I think the question 9 is D

Answer 38

correct!

Answer 39

Ok teacher....

Answer 40

ok Sariah I need to go and eat something now - good luck with the future and be more positive in your own abilities!

Answer 41

Ok dear... Have a nice day...

Answer 42

can i have your E-mail?

Answer 43

sure - it's openstudy@anjum.otherinbox.com
by the way - just so that you don't get the wrong impression - I am a VERY happily married man :-)

Answer 44

Ok
Taht is good....Good luck! If i have question in the fucture, can i send you the E-mail to you? or what do you think?

Answer 45

no problem - got to go now - should be back here in about 2 hours....

Answer 46

I see you are very good man... i wish every one be like you... Bye Bye!

Answer 47

Not today maybe but in the end of november... is it ok... or one day of this.. bye and keep being so you are

Answer 48

Bye Bye"

Answer 49

What the?