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Mathematics 7 Online
OpenStudy (anonymous):

The velocity of a 2.4 kg particle changes from 3i-6j to -6i +4j m/s. What is its change in kinetic energy? @Physics

OpenStudy (amistre64):

KE = (1/2)*m*v^2 i believe. ill have to google it to dbl chk

OpenStudy (amistre64):

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OpenStudy (amistre64):

2.4*(3^2+6^2)/2 would be the initial KE 2.4*(6^2+4^2)/2 would be the last KE would last - first equate to the change?

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