Simplify the following quotient of complex numbers into the form a + bi. -8-5i/6-3i
-33-54i/45
\[\frac{8-5i}{6-3i} * \frac{6+3i}{6+3i}\] Recall the properties of complex conjugates, and i^2 = -1 and solve ;)
Alfie thanks see i would have missed that I keep confusing myself on these types of problems then get frustrated and want to throw my computer across the room.
You're welcome, actually they are not too hard, each time you have a division you have to get rid of the i at the denominator so you multiply and divide for the complex conjugate. Then you have to do the products at the numerator, you'll have to recall that i^2 = -1. Now you are good to go. :)
yes thank you
when you are done verify with my answer above
-48-24i-30i-15i^2/36+18i-18i-9i^2 =-48-54i+15/36+9 =33-54i/45
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