Question

The velocity of a 2.4 kg particle changes from 3i-6j to -6i +4j m/s. What is its change in kinetic energy? @Mathematics

Answer 1

\[(1/2 *2.4 *\sqrt{3^2 + 6^2}) -(1/2 *2.4 *\sqrt{6^2 + 4^2})\]I think...

Answer 2

what is equation for kinetic energy

Answer 3

1/2mv^2

Answer 4

then icecream answer is right

Answer 5

the answer isn't right

Answer 6

I think I did initial-final kinetic energy so trying switching it around.