Question

2^(x+2)=6^(2x-5)
I do not know how to solve this problem. Help is greatly appreciated...thanks.

Answer 1

solve for x...
x+2=0
x=-2

2x-5=0
2x=5(divide both sides by 2 to eliminate 2)
x=5/2

substitute values of x..

2^(-2+2)=6^(2(5/2)-5)
1=1 :D

Answer 2

You will need to use the log law:
\[\log(a^{x}) = xlog(a)\]
You can take the log of both sides of the equation and then you can solve for x