Question

0, 4, 8 find an equation with these solutions

Answer 1

\[x^3-12 x^2+32 x \]

Answer 2

\[(x-0)(x-4)(x-8)\]Multiply them.

Answer 3

generally an equation of the form:
\[(x-c_1)(x-c_2)...(x-c_n)=0\]where all the "c" terms are constants means that the "c" terms are all the solutions of tis equation.
using this you should be able to work out the answer you want.

Answer 4

saifoo.khan your answer is wrong

Answer 5

No, it can't be.

Answer 6

chk your question

Answer 7

loll i did and it says wrong

Answer 8

look at what I typed out - that should give you a BIG hint

Answer 9

it says its wrong ):

Answer 10

sigh...it should be:
(x-0)(x-4)(x-8)=0
which simplifies to:
x(x-4)(x-8)=0

Answer 11

And then finally to answer i wrote.

Answer 12

ur right saifoo... my homework much just be stupid

Answer 13

which expands to:
\[x^{3}-12x^{2}+32x=0\]
you omitted the "= 0" on the RHS.

Answer 14

Online hw sucks at formatting. >_<

Answer 15

oh duh me! i forgot to set it equal to zero